510=2x^2+64x

Solution for 510=2x^2+64x equation:

510=2x^2+64x

We move all terms to the left:

510-(2x^2+64x)=0

We get rid of parentheses

-2x^2-64x+510=0

a = -2; b = -64; c = +510;
Δ = b2-4ac
Δ = -642-4·(-2)·510
Δ = 8176
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{8176}=\sqrt{16*511}=\sqrt{16}*\sqrt{511}=4\sqrt{511}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-64)-4\sqrt{511}}{2*-2}=\frac{64-4\sqrt{511}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-64)+4\sqrt{511}}{2*-2}=\frac{64+4\sqrt{511}}{-4}
$